pphp中将时间差转换为字符串提示的实现代码

pphp中将时间差转换为字符串提示的实现代码

php编程 2023-06-09 09:24:02 1年以前

如微博

这看起来更加人性化,好吧,上代码 代码如下:

<?php class timeAgo { static $timeagoObject; private $rustle; private $unit;

private function __construct() {

} private function __clone(){ } public static function getObject() { if(! (self::$timeagoObject instanceof self) ) self::$timeagoObject = new timeAgo();

return self::$timeagoObject; } private function count_int($unix_C) // main function { if(! (isset($unix_C) || is_numeric($unix_C)) ) return 'don\'t find parameter';

$d = time()-$unix_C ; // $d - unix time difference value $d_int =(int)floor($d/60) ; // minimum unit -- minutes unix/60

$this->unit = 0 ; // is minutes,hour or day?

if($d_int < 60){ // minutes in one hour 3600 $this->rustle = $d_int; $this->unit = 1; } else if($d_int < 720){ //hour in one day 3600*12 $this->rustle = floor($d_int/60); $this->unit = 2 ; } else if($d_int < 7200){ //day in ten days 3600*12*10 $this->rustle = floor($d_int/720); $this->unit = 3 ; } else{ $this->rustle = $d ; $this->unit = 4 ; } } public function piece_str($C) { $this->count_int($C);

$u = ''; switch( $this->unit ) { case 1: $u = 'minute'; break; case 2: $u = 'hour'; break; case 3: $u = 'day'; break; case 4: $u = ''; break; case 0: return 'sorry , get time is fail'; } if($this->unit < 4) { if($this->rustle > 1) return (string)$this->rustle.$u.'s ago'; else if($this->rustle == 1) return (string)$this->rustle.$u.'ago'; else return 'Just now'; } } /* example: $ago = timeAgo::getObject(); * echo $ago->piece_str($unix); * // 2 days ago */ } ?>

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