PHP HTML JavaScript MySQL代码如何互相传值的方法分享

PHP HTML JavaScript MySQL代码如何互相传值的方法分享

php编程 2024-12-24 23:38:04 6个月前

1.PHP

  a.PHP -> HTML & JavaScript

  额 超简单,我也要写= =~

  html代码中

<input type="" readonly="readonly" style='background-color:#DCDCDC' value=<?php echo $perinfo[ID];?> />    JavaScript代码中 代码如下:

<script type="text/javascript"> var ability=<?php echo JSON($array);?>; </script>

  b.PHP <-> MySQL

  php代码中 代码如下:

<?php $dbcnx = @mysql_connect ( "localhost", "root", "1234" ); if (! $dbcnx) { echo ("Unable to connect to the " . "database server at this time."); exit (); }

if (! @mysql_select_db ( "pms" )) { echo ("Unable to locate the joke " . "database at this time."); exit (); } mysql_query ( "SET NAMES 'GB2312'" );

$q=mysql_query("select * from ability where ALV = 1"); while($row=mysql_fetch_array($q)){ $array1[] = $row[AName]; } ?>

2.HTML

  a. HTML -> PHP (POST方式)

  html代码中 代码如下:

<form id="form" name="form" method="POST" action="do.php"> <input type="hidden" id="count" name="count" value="1"/> <input type="submit" name="Submit" value="Search"/> </form>

  do.php 文件代码中 代码如下:

<?php echo $_POST['count']; ?>

  b. HTML -> JavaScript

  JavaScript代码中 (可获得,可更改) 代码如下:

<script type="text/javascript"> var te = document.getElementById("count"); te.value = 1; </script>

3.JavaScript

  a. JavaScript -> HTML (通用法, 未验证)

  JavaScript代码中 代码如下:

<script type="text/javascript"> function f(){ var id = "2"; var a = document.getElementById("a"); a.href.replace("(n)", id); } </script>

html代码 代码如下:

<a id="a" href="ExportArticle.action?articles=(n)"/>

  b. JavaScript -> PHP

  通过html的转接

  1.JavaScript代码先给html 代码如下:

<script type="text/javascript"> var i = 1; var te = document.getElementById("count"); te.value = i; </script>

  2.html代码给php 代码如下:

<form id="form" name="form" method="POST" action="do.php"> <input type="hidden" id="count" name="count" value="1"/> <input type="submit" name="Submit" value="Search"/> </form>

  3.do.php接收到 代码如下:

<?php echo $_POST['count']; ?>

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